What are the vertical asymptotes of the function f(x) = 4x+8/x^2+3x-4

1 and -4

Step-by-step explanation:

The vertical asymptote of a function is gotten by equating the denominator of such function to zero.

Given

f(x) = 4x+8/x^2+3x-4

The vertical asymptotes is expressed as;

x^2+3x-4 = 0

Factorize

x^2+4x-x-4 = 0

x(x+4) -1 (x+4) = 0

(x-1)(x+4) = 0

x-1 = 0 and x+4 = 0

x = 1 and x = -4

Hence the vertical asymptotes of the function are 1 and -4

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: