In triangle JKL, sin(b°) = three fifths and cos(b°) = four-fifths. If triangle JKL is dilated by a scale factor of 2, what is tan(b°)? tan(b°) = five thirds
tan(b°) = four thirds
tan(b°) = three fourths
tan(b°) = five fourths

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the answer is 3/4!

Step-by-step explanation:

the sides would be doubled, meaning the new fraction for the dilated is 6/8. therefore, we can simplify this back to 3/4!

the answer is 3/4

Step-by-step explanation:

I took the test and got it right

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i think the answer is b.

step-by-step explanation:

not 100% sure though.