What is the interval, of length 0.01, of the function f(x)=x^3-6x^2+1, given that the root lies in the interval [5.5, 6]? Use the bisection method.

about 0.75 hours

step-by-step explanation:

h is the x-coordinate of the vertex

step-by-step explanation:

we have

in this function

the point represent the vertex of the function

so

h is the x-coordinate of the vertex

k is the y-coordinate of the vertex