During a flu vaccine shortage in the United States, it was believed that 45 percent of vaccine-eligible people received flu vaccine. The results of a survey given to a random sample of 2,350 vaccine-eligible people indicated that 978 of the 2,350 people had received flu vaccine. Construct a 99 percent confidence interval for the proportion of vaccine-eligible people who had received flu vaccine. Use your confidence interval to comment on the belief that 45 percent of the vaccine-eligible people had received flu vaccine. Suppose a similar survey will be given to vaccine-eligible people in Canada by Canadian health officials. A 99 percent confidence interval for the proportion of people who will have received flu vaccine is to be constructed. What is the smallest sample size that can be used to guarantee that the margin of error will be less than or equal to 0.02

Part A:  99% CI is given by : (0.38998, 0.44236)

Part B:

The given proportion 45 % or 0.45 is not included in the 99% confidence interval which is 0.39- 0.44 . So it is not consistent with the statement that 45 % got vaccinated.

Part C:

There should be at least 4148 vaccine eligible people in Canada to guarantee that the margin of error will be less than 0.02

Step-by-step explanation:

Part A:

The test statistic p^ ±z sqrt (p`q`/n) will be used because

It is a random sample and both np^≥10 also nq^≥10 so the large sample interval procedure is used.

Here

p= proportion of vaccine- eligible  people who received flu vaccine

Sample size= n= 2350

Sample success= p^=978/2350= 0.4161

Sample failure= q^= 1-p`= 1- 0.4161= 0.5838

For 99% CI the z- value is 2.576

Using the test static

p^ ±z sqrt (p^q^/n)

0.4161± 2.576 sqrt( 0.4161*0.5838/2350)

0.4161± 2.576 * 0.010167

0.4161± 0.02619

(0.38998, 0.44236)

Part B:

The given proportion 45 % or 0.45 is not included in the 99% confidence interval which is 0.39- 0.44 . So it is not consistent with the statement that 45 % got vaccinated.

Part C:

z* sqrt ( p^q^/n) ≤ 0.02

sqrt ( p^q^/n) ≤ 0.02/z

Taking square of both sides

( p^q^/n) ≤ [0.02/z]²

Reciprocating both sides

n/p^q^ ≥[ z/ 0.02]²

n≥[ z/ 0.02]²p^q^

n≥  z²p^q^/[  0.02]²

Putting the values

n ≥(2.576)² (0.5)(0.5)/ 0.2²

n≥ [2.576 /2 (0.02) ]²

n≥4,147.36

There should be at least 4148 vaccine eligible people in Canada to guarantee that the margin of error will be less than 0.02

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation:

no he doesnt because "-16' is negatiive

step-by-step explanation: