Drag and drop the answers to the boxes to correctly complete the proof. Given: Rhombus JKMH with diagonals intersecting at point P

Rhombus J K M H with diagonals J M and H K intersecting at P

Prove: JM⎯⎯⎯⎯⎯⊥HK⎯⎯⎯⎯⎯⎯

By the definition of Response area, JK⎯⎯⎯⎯⎯≅KM⎯⎯⎯⎯⎯⎯ and by the reflexive property of congruence, KP⎯⎯⎯⎯⎯≅KP⎯⎯⎯⎯⎯ . Because the diagonals of a rhombus bisect a pair of opposite angles, ∠JKP≅∠MKP , making △JKP≅△MKP by the Response area. Because Response area, ∠JPK≅∠MPK, and these angles are right angles because two angles that form a linear pair are congruent, thereby making JM⎯⎯⎯⎯⎯⊥HK⎯⎯⎯⎯⎯⎯ by the definition of perpendicular segments.

congruent segmentsa rhombusa parallelogramSSS congruence postulateASA congruence postulateSAS congruence postulateCPCTCthey are adjacentvertical angles are congruent

32

step-by-step explanation:

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )

25/14 or 1.

step-by-step explanation:

the dots mean that it has infinitely more numbers behind it