Let sin(2x)-sin(x)=0, where 0 ≤ x < 2pi. What are the possible solutions for x?

Step-by-step explanation:

sin2x - sinx = 0

2sinxcosx - sinx = 0

(Double Angle Formula)

sinx(2cosx - 1) = 0

Either sinx = 0 or cosx = 1/2.

When sinx = 0,

x = 0 or x = π.

When cosx = 1/2,

x = π/3 or x = 5π/3.

Hence the solutions are

x = 0, x = π/3, x = π or x = 5π/3.

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: