Have to find x, y and z

x=2, y=5

Step-by-step explanation:

the triangle that x is in is a right triangle (don't remember the theorem sorry)

use pythagorean theorem (a^2 + b^2 = c^2)

x is the hypotenuse(c)

1 squared plus /3 squared =c squared

1+3= c squared

4= c squared

c=2

x=2

find y using pythagorean theorem as well

/12 squared plus 2 squared = y squared

y is the hypotenuse

12+4=y squared

16= y squared

4=y

add one to account for that extra little piece

y=5

... I don't see z

∞ this is your sign

you need to give us more information since we can't answer