The failure of a circuit board interrupts work that utilizes a computing system, until a new board is delivered. The delivery time, Y, is uniformly distributed on the interval two to six days. The cost of a board failure and interruption includes the fixed cost c0 of a new board and a cost that increases proportionally to Y2. If C is the cost incurred, C = c0 + c1Y2. A) Find the probability that the delivery time exceeds two days.
B) In terms of c0 and c1, find the expected cost associated with a single failed circuit board.

a) 1  ( 100% )

b)   Co + 46/3 C1

Step-by-step explanation:

Delivery time = Y

Interval = 2 to 6 days

cost incurred ( C ) = Co + C1 Y^2

a) determine the probability that the delivery time exceeds two days

since the delivery time is uniformly distributed on the interval 2 to 6 days the probability of having a delivery time > 2 days will be = 1

b) Determine the expected cost associated with a single failed circuit board

E ( Y^2 ) = 46/3

hence the cost associated with a single failed circuit board =

E ( C ) = Co + 46/3 C1

attached below is a detailed solution

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

all three statements are true

step-by-step explanation:

a shipping fee of 5% is charged online with every item purchased online

first let's just take each option and calculate them based on this, to see if the answers matched

keith buys a 40 dollar book

40 x 0.05 = 2

therefore there will be a two dollar fee on keith's book

40 + 2 =42

the first statement is true

a chair costs $80

80 x 0.05 = 4

80 + 4 = 84

the second statement is true

george buys a 20 dollar calculator

20 x 0.05 = 1

20 + 1 = 21

the third statements are true

all three statements are true