How much energy is absorbed by 250.0 g of water when its temperature rises from 25.0 ºC to 88.5 ºC? Specific heat capacity of water is 4.184 J/gºC.

.

(4.18 J/g°C) x (100.0 mL x 1.000 g/mL) x (37 - 4.0)°C = 13794 J = 13 kJ

2.  

(455 J) / (25.0 g) / (155 - 25)°C = 0.140 J/g°C

3.  

(4.184 J/g°C) x (20.0 g) x (303.0 - 283.0)°C = 1674 J

5.  

(0.129 J/g °C) x (85.0 g) x (200.0 - 10.0)°C = 2083 J

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I think this is the right answer, I am very, very sorry if I'm wrong

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where is the question is there is a formula or is there not one

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