Ray starts walking to school at a rate of 2 mi/h. Ten minutes later, his sister runs after him with his lunch, averaging 6 mi/h. b. Solve the system
to determine how much time it took Ray's sister to catch up to him.
Your answer

Ray walks 15 minutes prior to his sister and walk for 5 minutes to catches up

Step-by-step explanation:

The computation of the time taken is as follows:

Let us assume the Ray time be t

So his sister time would be t - 10

Since Ray distance is 2t

So his sister distance is 6(t - 10) = 6t - 60

As the distance is the same

So, the following equation must be made    

2t = 6t - 60

 -4t = -60

t = 15

Therefore Ray walks 15 minutes prior to his sister and walk for 5 minutes to catches up

i think that you should ask google for the answer to that problem because if we don't know it google does

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.