If a game player scored a 27 on the first game and a 39 on the second game, which number statement can be used to find what the player needs to score on the third game (S) to have a mean (average) score of 36?
A. 27 +39+ S3 = 36
B. 363 = 27 +39 + S
C. (36 + 3) + S +27 +39
D. (27 +39 + S) + 3 = 36

none of them are right...

Step-by-step explanation:

(27 + 39 + S)/3 = 36

27 + 39 + S = 36(3)

27 + 39 + S = 108

S = 108 - 39 - 27

S = 42

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.