What is the equation in point-slope form of a line that passes through the points (5, −3)(5, −3) and (−2, 9)(−2, 9) ? y−3=−2(x 5)y−3=−2(x 5) y 3=−127(x−5)y 3=−127(x−5) y 3=−2(x−5)y 3=−2(x−5) y−3=−127(x 5)

The equation in point-slope form of a line that passes through the points (5, -3) and (-2, 9) is

For a line that passes through the points (x₁, y₁) and (x₂, y₂), the point-slope form of the equation of the line is:

where m is the slope given by the formula:

The line passes through the points (5, -3) and (-2, 9)

That is, x₁ = 5, y₁ = -3, x₂ = -2, y₂ =  9

Calculate the slope (m) by substituting x₁ = 5, y₁ = -3, x₂ = -2, y₂ =  9

into the equation

Substitute x₁ = 5, y₁ = -3, and m = -12/7 into the line equation

Therefore, the equation in point-slope form of a line that passes through the points (5, -3) and (-2, 9) is

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q1 a person or thing situated away or detached from the main body or system. a cluster is a a mash of many things.

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step-by-step explanation:

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17