Find the area of the isosceles triangle formed by points of intersection of the parabolas y=-x2+9 and y=2x2+3 and the origin.

10

Step-by-step explanation:

*I’m assuming that you meant y = 2x^2-3 because that is what my RSM problem was and it was exactly the same problem other than that.* First you want to find the points of intersection of the two parabolas. You can choose to graph them or do any other method. Anyways, the points of intersection are: (2,5) and (-2,5). You now want to add (0,0). So obviously (2,5) to (-2,5) is the base and it is 4 units. The height is 0 to 5 which is 5 units. Do (4*5)/2 and you get 10. Hope this helped you with your RSM and let me know if I assumed correctly.

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction