The top of the cliff is 142 m above sea level. Currently the boat is 100 metres from the buoy and the angle of depression from the top of the cliff to the boat is 64º. Find the distance from the top of the cliff to the buoy. diagram not to scale Top of cliff 142 boat buoy Base of cliff (sea level) 100 m. The distance from the top of the cliff to the buoy is type your answer...

221.0 m

Step-by-step explanation:

First, find x using trigonometric ratio formula:

Reference angle = angle of depression = angle of elevation = 64°

Opposite side length = 142 m

Adjacent side length = x

Thus:

tan(64) = 142/x

x*tan(64) = 142

x = 142/tan(64)

x = 69.3 (nearest tenth)

Next, find distance from top of the hill to the buoy using Pythagorean Theorem.

Let the distance be y.

We would have:

y² = 142² + (69.3 + 100)²

y² = 20,164 + 28,662.49

y² = 48,826.49

y = √48,826.49

y = 221.0 m (nearest tenth)

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.