What is the vertex and the equation of the axis of symmetry of the graph of y=x^2-6x-7

a. vertex: (–16, 3)
a. o.s: x = –16

b. vertex: (–3, 20)
a. o.s: x = –3

c. vertex: (3,–16)
a. o.s: x = 3

d. vertex: (20, –3)
a. o.s: x = 20

Option C is correct

Vertex: (3, -16) and axis of symmetry is x = 3

Step-by-step explanation:

The axis of symmetry for a parabolic general equation is given by:

           ....[1]

Vertex of the equation is:

As per the statement:

The graph of the equation is:

         ....[2]

On comparing with general parabolic equation i.e   we have;

a = 1, b = -6 and c = -7

By [1] we have;

Substitute the given values we have;

Simplify:

x = 3

Substitute the value  of x= 3 in [2] we have;

Therefore, the vertex of the given equation is: (3, -16) and axis of symmetry is x = 3

it should be a and d. lmk if i'm wrong xd

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17