Write the equation for the line in slope-intercept form (2,-3) (-1/2) ( HELP PLEASE )

A linear equation is a fancy term for a straight line, which can be created by joining 2 points.

A point can be defined by (x, y), where x and y are the horizontal distance and the vertical distance respectively from point (0,0) (called the origin).

There are 3 ways to define a line:

(1) The slope-intercept form

y = mx + b, in which m is the slope, b is the y-intercept, where the line crosses the vertical axis at (0, b). If values of m and b are given, you can substitute and write the equation right away.

The slope, m, is calculated by rise (vertical difference between 2 points on the line) divided by run (horizontal difference between the 2 points on the line)

Step-by-step explanation:

or example, if 2 points on the line are

(x1, y1) and (x2, y2)

Then slope = (y1– y2)/(x1 — x2)

If m > 0, then the line rises to the right.

If m = 0, then the line is horizontal.

If m < 0, then the line rises to the left.

If the line is in the form x = c, where c is a constant, then the line is vertical.

(2) Point slope form

m = (y — y1)/(x — x1), when (x1, y1) and m are given.

In other words,

m(x — x1) = y — y1

mx — m(x1) = y — y1

y = mx — m(x1) + (y1)

Note that b = -m(x1) + (y1)

(3) linear form

ax + by + c = 0, where a, b, and c are constants.

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

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