Write an equation in slope intercept form that passes through the point (2,-2), and has a slope that equals -2 (please hurry)

y = -2x + 2

Step-by-step explanation:

Plug in the point and slope into y = mx + b, and solve for b:

y = mx + b

-2 = -2(2)  + b

-2 = -4 + b

2 = b

Plug in the slope and y intercept into y = mx + b

y = -2x + 2

So, the equation is y = -2x + 2

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