Can someone help me please i’m stuck

Point of intersection of diagonal is: (-4,2)

x-coordinate = -4

y-coordinate = 2

Step-by-step explanation:

The diagonals of parallelogram bisect each other, So we need to find the midpoint of the diagonal to find the point of intersection. The midpoint of both diagonals will be same.

Consider the diagonal BD

We have B (-6,-5) and D (-2,9)

We need to find midpoint of the diagonal BD.

The formula used is:

We have

Putting values and finding midpoint

So, We get Midpoint(-4,2)

We will get the same midpoint if we find for other diagonal AC.

So, Point of intersection of diagonal is: (-4,2)

x-coordinate = -4

y-coordinate = 2

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

answer: answer is b.

[m < b = 120º]

step-by-step explanation: