Mathematics, 28.01.2021 09:30 ComicSans10
Rewrite (6x3 + 9x2 + 7)/(2x3 + 3x2) in the form q(x) + r(x)/b(x) where q(x) = quotient, r(x) = remainder, and b(x) = divisor.
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If sec theta = 5/3 and the terminal point determined by theta is in quadrant 4, then
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Having a hard time understanding this question (see attachment).
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Rewrite (6x3 + 9x2 + 7)/(2x3 + 3x2) in the form q(x) + r(x)/b(x) where q(x) = quotient, r(x) = remai...
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