The 150 students in the band will attend an awards assembly. A random survey of 30 was done to see what type of pizza they would order. 10 Pepperoni 15 Cheese • 5 Hamburger Based on the survey results, which of these is the best prediction of the types of pizza wanted by the 150 students? A. There are 40 students who want pepperoni B. There are 100 students who want either pepperoni or hamburger C. There are 10 more students who will want cheese than hamburger D. There are 5 more students would want pepperoni than hamburger (PLEASE ANSWER ILL GIVE BRAINLIEST)

None are correct.

Step-by-step explanation:

10/30 wanted pepperoni, so 1/3 of them wanted pepperoni.

15/30 wanted cheese, so 1/2 wanted cheese.

5/30 wanted hamburgers, so 1/6 wanted hamburgers.

You can use this information to estimate the number of the 150 students who wanted each.

1/3 of 150 = an estimated 50 wants pepperoni

1/2 of 150 = an estimated 75 wants cheese

1/6 of 150 = an estimated 25 wants hamburgers

Now you can use this to see which one is true.

A. There are 40 students who want pepperoni

not true, there are 50

B. There are 100 students who want either pepperoni or hamburger

50(pepperoni) + 25(hamburger) = 75, so this is not true

C. There are 10 more students who will want cheese than hamburger

75(cheese) - 25 (hamburger) = 50, so this is not true.

D. There are 5 more students would want pepperoni than hamburger

50 (pepperoni) - 25 (hamburger) = 25, so this is not true

None of these answers are correct

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3