Find the Area of the figure below, composed of a parallelogram and two semicircles. Round to the nearest tenths place. See
The picture please help test

100.3 sqr. units

Step-by-step explanation:

Area of the composite figure = area of parallelogram + area of 2 semicircles

✔️Area of parallelogram = base * height

Base = 10

Height = 5

Area of parallelogram = 10*5 = 50 sqr. units

✔️Area of 2 semicircles = 2(½*πr²)

radius (r) = ½*8 = 4

Area of two semicircles = 2(½*π*4²)

Area of two semicircles = π*16 = 50.3 sqr.

✔️Area of composite figure = 50 + 50.3 = 100.3 sqr. units

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: