WILL MARK BRAINLIEST Which equation is an equation of a circle with a radius of 3 and its center is at (5, -2)? (x - 5)² + (y + 2)² = 3

(x - 5)² + (y + 2)² = 9

(x + 5)² + (y – 2)² = 3

(x + 5)² + (y - 2)² = 9

(x + 5)² + (y – 2)² = 3

Step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°