If FE is a midsegment of ABCD, find DF.
A. 2
B. 3
C. 5
D. 6

C

Step-by-step explanation:

Remark

A midsegment is 1/2 the size of the side that it is parallel to.

Equation

6x - 6 = 2*(x + 3)                    Remove the brackets

6x - 6 = 2x + 6                       Subtract 2x from both sides

6x - 2x - 6 = 6                        Combine

4x - 6 = 6                               Add 6 to both sides

4x = 6 + 6                              Combine

4x = 12                                   Divide by 4

x = 12 / 4

x = 3

Find DF

But that's not the answer.

DF = x + 2

DF = 3 + 2

DF = 5

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d