Heba ate \dfrac{1}{12} 12 1 start fraction, 1, divided by, 12, end fraction of a box of cereal. Now the box is \dfrac{3}{4} 4 3 start fraction, 3, divided by, 4, end fraction full. What fraction of a full box was there before Heba ate

9514 1404 393

  5/6

Step-by-step explanation:

If q is the quantity of cereal in the box before Heba ate some, the problem tells us ...

  q - 1/12 = 3/4

  q = 3/4 + 1/12 = 9/12 + 1/12 = 10/12

  q = 5/6

There was 5/6 of a box before Heba ate.

i think it is 70

step-by-step explanation:

it is true

step-by-step explanation:

all the combinations add up i used   calculator