A stockbroker knows from experience that the probability that a client owns stocks is 0.60. P(A) The probability that a client owns bonds is 0.50. P(B) The probability that the client owns bonds if he/she already owns stock is 0.55 What is the probability of a client owning stocks OR bonds

the probability of a client owning stocks OR bonds is 0.825

Step-by-step explanation:

The computation of the probability of a client owning stocks OR bonds is given below:

= P(stocks) + P(bonds) - P(stocks and bonds)

= 0.60 + 0.50 - (0.55 × 0.50)

= 0.60 + 0.50 - 0.275

= 0.825

Hence, the probability of a client owning stocks OR bonds is 0.825

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true