Please actually help me! I've asked this question twice and the first time, nobody answered and the second time, some idiot just said "use photomath" and i reported it and it hasn't gotten deleted. So I'm asking again! I'll give tons of points + Brainliest if correct! Please answer ASAP

AC = 46BD = 50

Step-by-step explanation:

The property of diagonals of a parallelogram:

diagonals bisect each otherDiagonal ACAC = 2(3y - 1)AC = 2(y + 15)

Compare and solve for y:

3y - 1 = y + 153y - y = 15 + 12y = 16y = 8AC = 2(3*8 - 1) = 46Diagonal BDBD = 2(5x)BD = 2(3x + 10)

Compare and solve for x:

5x = 3x + 102x = 10x = 5BD = 2*5*5 = 50

The answer is:

AC = 46BD = 50

Correct choice is A

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12