The probability of a potential employee passing a training course is 86%. If you selected 15 potential employees and gave them the training course, what is the probability that more than 11 will pass the test? a. 0.648
b.0.900
c. 0.352
d. 0.852

d. 0.852

Step-by-step explanation:

For each employee, there are only two possible outcomes. Either they will pass the test, or they will not. The probability of an employee passing the test is independent of other employees. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

The probability of a potential employee passing a training course is 86%.

This means that

Sample of 15.

This means that

What is the probability that more than 11 will pass the test?

So

The correct answer is given by option d.

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option