Pl will give 20 points An expression is shown below:
4(m + 3 + 5m)

Part A: Write two expressions that are equivalent to the given expression. (3 points)

Part B: Show that one of your expressions in Part A is equivalent to the given expression using algebraic properties. Explain which properties you used. (4 points)

Part C: Show that your other expression from Part A is equivalent to the given expression by substituting a number for m. (3 points)

A) 48m + 12 and 3(2m + 4 + 14m)

B) 48m + 12 is equivalent to 6(m + 2 + 7m) because if you distribute the 6 to everything inside the parentheses, you get 6m + 12 + 42m. This can be simplified further by adding 6m and 42m together, leaving you with 48m + 12.

C) m = 2

6(m + 2 + 7m)

6[2 + 2 + 7(2)]

6(4 + 14)

6(18)

108

3(2m + 4 + 14m)

3[2(2) + 4 + 14(2)]

3(4 + 4 + 28)

3(8 + 28)

3(36)

108

108 = 108

Step-by-step explanation:

A) You can simplify 6(m + 2 + 7m) by distributing the 6, (after simplification) resulting in 48m + 12.

Since 6/3 = 2, you can replace the 6 with 3 and multiply everything within the parentheses by 2.

B) This part was explained in the answer. If you have further questions please ask :)

C) I substituted m for 2 in both 6(m + 2 + 7m) and 3(2m + 4 + 14m). Since they both equal 108, the equations are equivalent.

Step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.