Given x is the midpoint of wy and vz . Prove xwv is congruent to xyz (Will give brainliest)

Step-by-step explanation:

if you're asking for the proof and reasoning thing

1. yw⊥xz, yw bisects xz ⇒ given

2. xw≅zw ⇒ w is a midpoint

3.∠ywx and ∠ywz are right angles, so ∠ywx≅∠ywz ⇒ definition of perpendicular bisector

4. yw≅yw ⇒ reflexive

5. Δwxy≅Δwzy ⇒ SAS

6. xy≅zy ⇒ CPCTC

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

x coordinate is none

step-by-step explanation: