Mathematics, 30.01.2021 03:20 yalley1982

What is the solution to this system of equations. Use any method you choose 4x + 3y = 37
y = x - 4

Answers: 2

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Answers

Answer from: nculberson6

(7, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtract Property of Equality

Algebra I

Terms/CoefficientsCoordinates (x, y)Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

4x + 3y = 37

y = x - 4

Step 2: Solve for x

Substitution

Substitute in y: 4x + 3(x - 4) = 37Distribute 3: 4x + 3x - 12 = 37Combine like terms: 7x - 12 = 37[APE] Add 12 on both sides: 7x = 49[DPE] Divide 7 on both sides: x = 7

Step 3: Solve for y

Define equation: y = x - 4Substitute in x: y = 7 - 4Subtract: y = 3

Answer from: Quest

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

Answer from: Quest

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