On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the percent of scores that are: a) Between 90 and 100

34.134%

Step-by-step explanation:

Given :

Normal distribution ;

Mean, m = 100 ; Standard deviation, s = 10

Percentage score between 90 and 100

P(90 ≤ x ≤ 100)

Recall : Zscore = (x - m) / s

P[(90 - 100) / 10 ; (100 - 100) / 10]

P[(10/10 ; 0 / 10)]

P(Z ≤ 1) - P(Z≤0) (Using Z probability calculator)

0.84134 - 0.5

= 0.34134

= 0.34134 * 100%

= 34.134%

i can't read the graph

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet