Which is the equation in the slope-intercept form of the line that contains points E & F ? •4x-y=12
•y-4=4(x-4)
•x-4=4(y-4)
•y=4x-12

y = 4x - 12

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m =

with (x₁, y₁ ) = E(4, 4) and (x₂, y₂ ) = F(2, - 4)

m = = = 4 , then

y = 4x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (4, 4), then

4 = 16 + c ⇒ c = 4 - 16 = - 12

y = 4x - 12 ← equation of line

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation