Find the sum of the first 50 terms.
-6,-2,2,6

4600

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = - 2 - (- 6) = 2 - (- 2) = 6 - 2 = 4

This indicates the sequence is arithmetic with sum to n terms

= [ 2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = - 6 and d = 4 , then

= [ (2 × - 6) + (49 × 4) ]

     = 25(- 12 + 196)

     = 25 × 184

     = 4600