The shortest side of a triangle with angles 50°, 60°, and 70° has a length of 11.0. What is the length of the longest side rounded to the nearest tenth?

14

Step-by-step explanation:

Let us denote the longest side as "y"

✓According to trigonometry, Largest side and largest angle are always opposite while the shortest side and shortest angle are opposite.

✓ the length vof shortest sides=11

Then

Sin(50)/11 = sin(70)/ y

Cross multiply

Sin(59) × y = 11 × sin(70)

y= [11 × sin(70) ] / sin(50)

y= (11×0.9397)/0.7660

y=13.493

Hence, he length of the longest side rounded to the nearest tenth is 14

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

468

step-by-step explanation: