A 70 Kg man on a 10 kg bike has 1440 J of kinetic energy. How fast is the
man moving?

9514 1404 393

  6 m/s

Step-by-step explanation:

The formula for kinetic energy is ...

  KE = (1/2)mv² . . . . m is mass

Filling in the given values, we can solve for v.

  1440 J = (1/2)(70+10 kg)v^2

  (1440 J)/(40 kg) = v^2 = 36 m²/s² . . . . m is meters

  v = √(36) m/s = 6 m/s

The man is moving at  6 meters per second.

In terms of units analysis, the joule (J) is a derived unit equal to ...

  1 J = 1 kg·m²/s²

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

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