Anybody know how to do this ?

Part a: x=sqrt(104) in; Part b: x=sqrt(5) in

Step-by-step explanation:

Part a:

Because the figure has a right angle (signified by the square), it is a right triangle. Therefore, the Pythagorean Theorem, a²+b²=c² where c is the hypotenuse (longest side) and a and b are the legs (shorter sides), applies. Thus:

a²+b²=c²

The 15 in side is opposite the right angle, so it is the hypotenuse.

The 11 in side and x in side are not opposite the right angle, so they are legs.

11²+x²=15²

121+x²=225

(121+x²)-121=225-121

x²=104

sqrt(x²)=sqrt(104)

x=±sqrt(104)

Reject x=-sqrt(104) because a negative side length in a triangle is impossible. Therefore,

x=sqrt(104) in

Part b:

The figure is a right triangle. Therefore, the Pythagorean Theorem (a²+b²=c²) applies. Hence,

5²+(2x)²=(3x)²

25+4x²=9x²

(25+4x²)-4x²=9x²-4x²

25=5x²

5=x²

sqrt(5)=sqrt(x²)

x=±sqrt(5)

Reject x=-sqrt(5) because a negative side length is impossible.

The answer must be x=sqrt(5) in.

its 4 because 2 times 2 is 4, if you double the number two you get four

sure i'm up for it

step-by-step explanation: