Pls help with this problem

The table will be:

x              0      1       2      -1       3       1/3

y=3x-1     -1       2      5      -4      8       0

Step-by-step explanation:

We are given the equation: y = 3x-1 and we need to fill the table.

We have to put value of x and find value of y

When x = 0

y= 3(0)-1 = 0-1 = -1

So, x=0, y=-1

When x = 1

y=3(1)-1=3-1 = 2

So, x=1, y=2

When x = 2

y=3(2)-1=6-1 = 5

So, x=2, y=5

Now, we are given y=-4 and we need to find x

y=3x-1

-4=3x-1

-4+1=3x

3x=-3

x=-3/3 = -1

So, y = -4, x = -1

Now, we are given y=8 and we need to find x

y=3x-1

8=3x-1

8+1=3x

3x=9

x=9/3 = 3

So,  y = 8, x = 3

Now, we are given y=0 and we need to find x

y=3x-1

0=3x-1

0+1=3x

3x=1

x=1/3

So,  y = 0, x = 1/3

The table will be:

x              0      1       2      -1       3       1/3

y=3x-1     -1       2      5      -4      8       0

step-by-step explanation:

i am not sure sorry : c

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length