Six numbers form an arithmetic sequence with a common difference of 4. The sum of these numbers equals to 12. What are the six numbers? PLS ANSWER! ITS FINE IF YOU DONT SHOW WORK!

-8, -4, 0, 4, 8, 12

Step-by-step explanation:

The nth term Tn of  an arithmetic sequence with a common difference d and a first term a is given as

Tn = a + (n - 1) d

Hence if the first term is a and the common difference is d then

the

2nd term = a + 4

3rd term = a + (3 - 1) 4 = a + 8

4th term = a + (4 - 1) 4 = a + 12

5th term = a + (5 - 1) 4 = a + 16

6th term = a + (6 - 1) 4 = a + 20

If the sum of these six numbers is 12 then

a + a + 4 + a + 8 + a + 12 + a + 16 + a + 20 = 12

6a + 60 = 12

collect like terms

6a = 12 - 60

6a = -48

divide both sides by 6

a= -8

the numbers are

a = -8

2nd term = a + 4 = -8 + 4 = -4

3rd term = a + (3 - 1) 4 = a + 8 = -8 + 8 = 0

4th term = a + (4 - 1) 4 = a + 12 = -8 + 12 = 4

5th term = a + (5 - 1) 4 = a + 16 -8 + 16 = 8

6th term = a + (6 - 1) 4 = a + 20  = -8 + 20 = 12

step-by-step explanation:

let's assume

number of candles set =x

price of of x candles =p(x)

we are given

a candle maker prices one set of scented candles at $10 and sells an average of 200 sets each week

so, we get point as (200,10)

he finds that when he reduces the price by $1, he then sells 50 more candle sets each week

so, we can find slope

now, we can use point slope form of line

now, we can plug values

we can use point

and find b

now, we can plug it back

and we get

now, we can find revenue

we know that

revenue = price*quantity

so, we get