In ΔFGH, \overline{FH} FH is extended through point H to point I, \text{m}\angle FGH = (x-2)^{\circ}m∠FGH=(x−2) ∘ , \text{m}\angle GHI = (4x-5)^{\circ}m∠GHI=(4x−5) ∘ , and \text{m}\angle HFG = (x+19)^{\circ}m∠HFG=(x+19) ∘ . Find \text{m}\angle HFG. M∠HFG.

sorry, i can't understand your question. will later if you describe more clearly!

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step-by-step explanation:

should you really be posting this isn't math boi.

w'x is 0.

hope it

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet