Evaluate the integral by making the given substitution. (Use C for the constant of integration.) ∫ x^2√x^3+37 dx, u=x^3+37

The Given integral is :

∫x²√x³ + 37 dx ; u = x³ + 37

2/9(x³ + 37)^3/2 + C

Step-by-step explanation:

∫x²√x³ + 37 dx ; u = x³ + 37

∫x²√u dx

Since u = x³ + 37

Differentiate u with respect to x

du/dx = 3x²

du = 3x²dx

dx = du / 3x²

∫x²√u dx = ∫x²√u du/3x²

1/3x²∫x²√u du

1/3 ∫ √u du

Integrating √u with respect to u

1/3 ∫ u^1/2 du

1/3 [u^(1/2+1) / 1/2 + 1] + C

1/3 [u^3/2 / 3/2] + C

1/3 u^3/2 * 2/3 + C

1/3*2/3 u^3/2 + C

2/9 u^3/2

u = x³ + 37

2/9(x³ + 37)^3/2 + C

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

8

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2