You want to create a six-digit passcode number which is of the form ABCDEF for your iPad. The digit ‘A’ is restricted to a number 1 through 9. The digits B, C, D and E can be any number, but they cannot repeat. The digits F has no restriction. How many choices are there for the digit "A"?

If you are just using the digits from 1 to 6, the answer would be 6*5*4*3*2*1 = 720, because you have 6 choices for the units digit, and then 5 choices left for the tens, and then 4 choices left for the hundreds and so on. Similarly, if all the digits from 1 to 9 were allowed (with no digit repeated), then the answer would be 9*8*7*6*5*4 = 60480.

The tricky part comes when the digit 0 is allowed: suppose that you wanted to form a 6-digit number using digits from 0,1,...,9 without repeating a digit. Then 0 could not be the leftmost digit. So, starting from the left, you would have 9 choices for the leftmost digit (not allowing 0), then 9 choices again for the next digit (0 is now allowable but not the previous digit), then 8 choices for the next digit and so on, for a result of 9*9*8*7*6*5 = 136080.

answer: 30

step-by-step explanation: its 30 because im a basketball player and stephen curry hits most of his shots so if you put 30 you might make the shot goodluck

do you have an easier question cause this shh is hard like theheck

step-by-step explanation: