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1. 0 > 3x - 3 - 6

0 > 3x -9

9 > 3x

3 > x

It would be a closed circle starting from 3 going to the right.

2. 4x + 1 - 1 >/ -8

4x >/ -8

x >/ -2

It would be an open circle starting from -2 going to the right.

3. -1 </ 2n + 4 - 5

-1 </ 2n -1

0 </ 2n

Undefined.

4. -6 > 5n + 5 + 4

-6 > 5n + 9

-15 > 5n

-3 > n

It would be a closed circle going to the right

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl