What is the missing reason in step 5? Given: Ä intersects DĖ at point C.
Prove: ZDCB - ZECA
O linear pair postulate
O given
O definition of complementary angles
O congruent complements theorem
D
A
B
m.
Reasons
1
given
Statements
1
AB intersects DE at point
22DCB and BCE are a linear pair
32DCB is supp to ZBCE
4. BCE and ECA are a linear pair
5 BCE is supp to ZECA
8. DCB LECA
2
3
4
5
6
def of lin pr
linear pair post
def of lin pr
?
asupp. thm

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

yes

step-by-step explanation: