In \triangle VWX,△VWX, \overline{XV}\cong \overline{WX} XV
≅
WX
and \text{m}\angle W = 27^{\circ}.m∠W=27
∘
. Find \text{m}\angle X. m∠X.

m<X = 27 degrees

Step-by-step explanation:

From △VWX, since WX = XV, this mean that the triangle is isosceles

The base angle of an isosceles triangle are equal hence <W = <X

Since <W = 27 degrees, hence m<X = 27 degrees

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet