Determine if the given equations are parallel, perpendicular, or neither
4y=3x-4 and 4x+3y=-6

Perpindicular

Step-by-step explanation:

Solve each equation for y, or point Slope form.

y = mx + b

4y = 3x - 4 divide both sides by 4 to isolate the y.

y = 3/4x - 1

The second equation.

4x + 3y = - 6 subtract 4x from both sides

3y = -4x - 6 divide both sides by 3

y = -4/3 - 2

If you visualize line 1 having a Slope of 3/4, that is, for every 4 we move in the positive x direction, y will increase by 3, it slopes up from left to right crossing the y axis at (0,-1). The second line moves 3 in the positive x direction and decreases in y by 4, it slopes down from left to right crossing the y axis at (0,-2}.

Because the two lines have negative inverse slopes they are perpendicular. 3/4x and - 4/3x

ok

step-by-step explanation:

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.