Solve each of the following system of equations by substitution
y = -3x +5
2x+y=6

x = -1

y = 8

Step-by-step explanation:

y = -3x +5 . (1)

2x+y=6 .  (2)

(1) in (2)

2x + ( -3x + 5 ) =6

= 2x - 3x + 5 = 6

= -x + 5 = 6

Subtract 5 from each side

= -x = 1

x = -1

Now  put "-1" in for "x" in the first equation:

y = -3 (-1) +5

= y = 3 + 5

= y = 8

Hope that helps!

:D

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?