Graph the function h(x)= -1/5x^2+2x
Someone please help!

See QR code for link to Desmos

Step-by-step explanation:

The link I've provided makes graphing easy, but I'm hoping you're interested in doing this by hand. It's not that bad, and I hope you use the link to help you with what I'm about to share:

Easy point to plot: y-intercept (the y-value when x=0

h(0)=-1/5(0)^2+2(0)=0 -> (0,0) (With the link I've provided, you'll notice that the graph passes through (0,0)

Another point to plot is the vertex. Desmos shows this point to be (5,5). But without a graphing utility, there are a couple of steps you can do by hand:

Axis of symmetry formula:

If a quadratic is written as , then the axis of symmetry is .

Given that h(x)=-1/5x^2+2x, a=-1/5 and b=2. Plugging in this values into the axis of symmetry formula, we get:

In desmos, type in x=5. You'll see the line cut the parabola in half. That is the axis of symmetry. The last thing to do is find the y-value. That'll give us the vertex. Plug x=5 into h(x):

h(5)=-1/5(5)^2+2(5)=-25/5+10=-5+10=5. This gives us the point (5,5).

This algorithm works with all quadratics, and I encourage you to try it out, checking your work with Desmos.

what?

step-by-step explanation:

what do you need with. i love quadrants. can you tell me ?

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !