Write an equation in slope-intercept form that passes through (5, -8) and runs perpendicular to y = 5/2x + 4

y= (-2/5)x-6

Step-by-step explanation:

the slope of the line perpendicular the the given line is found by the formula m1.m2= -1 hence m2= -2/5

using the slope-intercept form

y+8= -2/5(x-5) y= (-2/5)x-6

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.