Henry went to an amusement park with $150.00 and spent all of it. He spent 1/5 of the money on parking He spent $37.00 on admission to the park He spent 40% of the money on food He paid a $10 fee for admission into a waterpark located inside the amusement park He spent the remainder of his money on games that cost $1.50 each How many games did Henry play?

8 games

Step-by-step explanation:

According to the problem, calculation of the given data are as follows,

Total amount = $150

Spent on Parking = 1/5 or 20% = $150 × 20% = $30

Spent on admission = $37

Spent on food = 40% = $150 × 40% = $60

Spent on admission in waterpark = $10

Each game cost = $1.5

So, let number of games played be X, then

$30 + $37 + $60 + $10 + $1.5X = $150

$137 + $1.5X = $150

1.5X = $150 - $137

1.5X = $13

X = $13 ÷ 1.5 = 8.67 or 8 games

Hence, Henry can play 8 games.