The first one ^

What is the vertex for the quadratic
y = 2(x-3)^2 - 4? Type as (h. k)

(3,-4)

Step-by-step explanation:

You can find the vertex where x = -b/2a

To find the values of a and b, it would be easier to write the equation in standard form, which is y = ax^2 + bx + c

y = 2(x^2 - 6x + 9) - 4

y = 2x^2 - 12x + 18 - 4

y = 2x^2 - 12x + 14

In this equation, a = 2 and b = -12.

So let's plug that into x=-b/2a

x = -(-12)/2(2)

x = 12/4

x = 3

Now we have the x, we can just plug that into the original equation and get the y coordinate for the vertex.

y = 2(x - 3)^2 - 4

y = 2(3 - 3)^2 - 4

y = -4

okay wait before i answer, is this for your points on a graph?